It is because of inability of ns^2 electrons of the valence shell to participate in bonding that

It is because of inability of ns^2 electrons of the valence shell to p

1.	It is because of inability of ns^2 electrons of the valence shell to participate in bonding that
Answer» `SN^(4+)` is REDUCING while `PB^(4+)` is oxidising `Sn^(2+)` is reducing while `Pb^(4+)` is OXIDIZING `Sn^(2+)` is oxidising while `Pb^(4+)` is reducing `Sn^(2+) and Pb^(2+)` are both oxidizing and reducing Answer :B