InterviewSolution
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InterviewSolution
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It is because of inability of `ns^(2)` electrons of the valence shell to particular in bonding that:A. `Sn^(2+)` is oxidizing while `Pb^(4+)` is reducingB. `Sn^(2+)` and `Pb^(2+)` are both oxidizing and reducingC. `Sn^(4+)` is reducing while `Pb^(4+)` is oxidisingD. `Sn^(2+)` is reducing while `Pb^(4+)` is oxidising |
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Answer» Correct Answer - D `Sn^(+2)toSn^(+4)` `(R.A.) Sn^(2+) lt Sn^(+4)` Stability order `Pb^(+4)toPb^(+2)` `(O.A.) Pb^(+2)gtPb^(+2)` Stability order (inert pair effect) |
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