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It is desired to increases the value of 80 cm^(3) of gas by 20% without changing the pressure to what temperature the gas be heated if its initial temperature is 25^(@)C? |
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Answer» Solution :The desired increases in the volume of gas `=20%` of 80 `cm^(3)=(80)/(100)xx20=16 cm^(3)` Thus, the FINAL volume of the gas `=80+16=96 cm^(3)` Now, `v_(1)=80 cm^(3) "" v_(2) =96 cm^(3)` `T_(1), 25^(@)C=298 K "" T_(2) ?` Applying Charle.s law, `(V_(1))/(T_(1))=(V_(2))/(T_(2)):.T_(2) =(V_(2)T_(1))/(V_(1))` `:. T_(2)=(96 cm^(3)xx298K)/(80 cm^(3))=357*6 K=357*6-273=84*6^(@)C :. T_(2)=84*6^(@)C` |
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