1.

It is desired to increases the value of 80 cm^(3) of gas by 20% without changing the pressure to what temperature the gas be heated if its initial temperature is 25^(@)C?

Answer»

Solution :The desired increases in the volume of gas
`=20%` of 80 `cm^(3)=(80)/(100)xx20=16 cm^(3)`
Thus, the FINAL volume of the gas `=80+16=96 cm^(3)`
Now, `v_(1)=80 cm^(3) "" v_(2) =96 cm^(3)`
`T_(1), 25^(@)C=298 K "" T_(2) ?`
Applying Charle.s law, `(V_(1))/(T_(1))=(V_(2))/(T_(2)):.T_(2) =(V_(2)T_(1))/(V_(1))`
`:. T_(2)=(96 cm^(3)xx298K)/(80 cm^(3))=357*6 K=357*6-273=84*6^(@)C :. T_(2)=84*6^(@)C`


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