Saved Bookmarks
| 1. |
It is desired to reduce the volume of 1000 cm of a gas by25%. To what temperature the gas be cooled if the initial temperature is 125^@C and the pressure remains constant ? |
|
Answer» SOLUTION :Given that `V_1 = 1000 cm^3, V_2 = 1000 - (1000 xx 25)/100= 750 cm^3` `T_1 = 125 + 273 = 398 K, "" T_2` = ? Since pressure remains CONSTANT, therefore, according to Charles. LAW, we have `V_1/T_1 = V_2/T_2` or `T_2= (V_2 T_1)/V_1 =(750 xx 398)/(1000) = 298K` Hence, the given gas should be cooled to `298 - 273 = 25^@C`to reduce its volume by `25%`. |
|