1.

It is desired to reduce the volume of 1000 cm of a gas by25%. To what temperature the gas be cooled if the initial temperature is 125^@C and the pressure remains constant ?

Answer»

SOLUTION :Given that
`V_1 = 1000 cm^3, V_2 = 1000 - (1000 xx 25)/100= 750 cm^3`
`T_1 = 125 + 273 = 398 K, "" T_2` = ?
Since pressure remains CONSTANT, therefore, according to Charles. LAW, we have
`V_1/T_1 = V_2/T_2`
or `T_2= (V_2 T_1)/V_1 =(750 xx 398)/(1000) = 298K`
Hence, the given gas should be cooled to `298 - 273 = 25^@C`to reduce its volume by `25%`.


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