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It is given that AB = BC and AD = EC. The ΔABE ≅ ΔCBD by ——— congruency.(a) SSS (b) ASA (c) SAS (b) AAS |
Answer» (c) SAS Given, AD = EC ⇒ AD + DE = DE + EC ⇒ AE = DC Also, AB = BC ⇒ ∠BCA = ∠BAC (isos. Δproperty) ⇒ ∠BCD = ∠BAE ∴ In Δs ABE and CBD, AB = CB (Given) AE = DC (Proved above) ∠BAE =∠BCD (Proved above) ∴ Δ ABE ≅ Δ CBD (SAS) |
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