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| 1. |
It is given that at x = 1, the function x^4-62x^2+ax+9 attains its maximum value, on the interval [0,2]. Find the value of a ? |
| Answer» SOLUTION :`f(X)=x^4-62x^2+ax+9,[0,2]f(x)=4x^3-124x+a` SINCE, f(x) attains MAXIMUM at x =1, f(x) = 0 at x =1 `thereforef(x)=0rArr4-124+a=0` a=120 | |