It is given that E=(2.859)/lambda cal//mol The energy associated with radiation of wavelength 4xx10^(-5) m will be

It is given that E=(2.859)/lambda cal//mol The energy associated with

1.	It is given that E=(2.859)/lambda cal//mol The energy associated with radiation of wavelength 4xx10^(-5) m will be
Answer» `71.5 kcal//mol` `35.75kcal//mol` `32.0 kcal//mol` `7.15 kcal//mol` Solution :GIVEN `E=(2.859)/lambdacal//mol` `lambda=4XX10^(-7)` `E=(2.859 cal//mol)/(4xx10^(-5)m)=71.5kcal//mol`