1.

It is given that the events A and B are such that P(A) = \(\frac{1}{4}\) , P(A/B) = \(\frac{1}{2}\) and P(B/A) = \(\frac{2}{3}\) . Then P(B) is(a) \(\frac{1}{2}\) (b) \(\frac{2}{3}\) (c) \(\frac{1}{6}\) (d) \(\frac{1}{3}\)

Answer»

Answer : (d) \(\frac{1}{3}\)

Given, 

P(B/A) =\(\frac{P(A\,\cap\,B)}{P(A)}\) 

\(P(A\,\cap\,B)= P(B/A)\times P(A)=\frac{2}{3}\times \frac{1}{4} = \frac{1}{6}\)
 

 Now P(A/B) = \(\frac{P(A\,\cap\,B)}{P(B)}\)

= \(\frac{1}{2} = \frac{1}{6}\times \frac{1}{P(B)} \implies P(B)=\frac{2}{6}= \frac{1}{3}\)


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