It ten volumes of dihydrogen gas reacts with five volumes of dioxygen gas, how many volumes of water vapour would be produced ?

It ten volumes of dihydrogen gas reacts with five volumes of dioxygen

1.	It ten volumes of dihydrogen gas reacts with five volumes of dioxygen gas, how many volumes of water vapour would be produced ?
Answer» Solution :`{:(2H_(2(G)),+,O_(2(g)),rarr,2H_(2)O_((g)),),(2V,,1V,,2V,):}` According to Gay-Lussac.s law, 2 volume dihydrogen gas COMBINE with 2 volume dioxygen gas to give 2 volume watervapour. So, it is 10 volume dihydrogen gas that combine with 5 volume dioxygen gas and FORM 10 volume water vapour.