1.

It was found at a certain dinner meeting that after every member had shaken hand with every other members, 45 handshakes were interchanged. How many members were present at the metting?

Answer»

et n be the member of person present in the meeting. The total number of handshakes is same as the number of ways of selecting 2 persons from among n persons.

The total number of handshakes = nC1 = 45

⇒ \(\frac{n(n-1)}{1 \times 2}\) = 45 

⇒ n2 – n – 90 = 0

⇒ (n – 10)(n + 9) = 0

⇒ n = 10, -9

n = 10 is acceptable.



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