1.

Itn =6l =1p orbitalm= 0.Thenthe maxelectronin porbitalare ……

Answer»

<P>6
2
4
10

Solution :N= 6,L =1m= + 10 = 1
`P_(x )p_(y)p_(z ) `
Total`E^(-) ` in porbitalare6 I`p_(y)` =2electron


Discussion

No Comment Found

Related InterviewSolutions