(iv) 29whose square 19 We(iii) 592J(ii) 2601(1) 1225(v) 8281new numbec – InterviewSolution

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1.	(iv) 29whose square 19 We(iii) 592J(ii) 2601(1) 1225(v) 8281new numbecase number should the given number be multiplied to geyumber in each case, find the number whose square is the new(iii) 3332(ii) 2156(viii) 2(1) 3675(vii) 3380(v) 9075(vi) 7623Piven number be divided to get a perfumber.
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