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जि ध =% + Nबे 571 Tam B Sed कर,ड |
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Answer» Use the identity : sec²A - tan²A = 1=> sec²A - 1 = tan²A=> (x + 1/4x)² - 1 = tan²A => tan²A = x² + 1/(16x²) + 1/2 - 1=> tan²A = x² + 1/(16x²) - 1/2=> tan²A = [x - 1/(4x) ]² => tan A = ± [ x - 1/(4x) ] => sec A + tan A = x + 1/(4x) ± [ x - 1/(4x) ] => sec A + tan A = x + 1/(4x) + x - 1/(4x) ==> 2x. . . . . . . . . . . . . . .OR=> sec A + tan A = x + 1/(4x) - x + 1/(4x) ==> 1/2x |
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