InterviewSolution
Saved Bookmarks
| 1. |
ज्ञात कीजिए `Sigma(2n^(2)-3n+5)` |
|
Answer» Correct Answer - `(n)/(6)(4n^(2)-3n+23)` `Sigma(2n^(2)-3n+5)` n वाँ पद `=T_(n)=2n^(2)-3n+5` n पदों का योगफल `=S_(n)=Sigma(2n^(2)-3n+5)` `=2Sigman^(2)-3Sigman+5Sigma1` `=2.(n(n+1)(2n+1))/(6)-(3n(n+1))/(2)+5.n` `=(n)/(6)[4n^(2)-3n+23]` |
|