1.

ज्ञात कीजिए `Sigma(2n^(2)-3n+5)`

Answer» Correct Answer - `(n)/(6)(4n^(2)-3n+23)`
`Sigma(2n^(2)-3n+5)`
n वाँ पद `=T_(n)=2n^(2)-3n+5`
n पदों का योगफल `=S_(n)=Sigma(2n^(2)-3n+5)`
`=2Sigman^(2)-3Sigman+5Sigma1`
`=2.(n(n+1)(2n+1))/(6)-(3n(n+1))/(2)+5.n`
`=(n)/(6)[4n^(2)-3n+23]`


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