JUL SHELT UT1.Given AABC is inscribed in the semicircle with diameter

1.	JUL SHELT UT1.Given AABC is inscribed in the semicircle with diameter AB. The area of AABCarea of the semicircle. If the measure of the smallest angle in AABCthe measure of the smallest angle in AABC is x then sin 2x is equal toTAB. The area of AABC equals 2/9 of the
Answer» BC²=AC²+AB² =8²+6² =64+36 =100 BC=10cm Area of biggest semicircle= 1/2 * 3.14 * r² =0.53.1455 =0.578.5 =39.25 cm² Area of 2nd Largest Semicircle = 0.53.14r² =0.53.143² =0.53.149 =14.13 cm² Area of smallest Semicircle = 0.53.14r² =0.53.144² =0.53.1416 =25.12cm² Area of Triangle = 1/2 bh = 0.568 =24 cm² Area of shaded region = (24+25.12+14.13) - 39.25 = 63.25-39.25 =24 cm²

JUL SHELT UT1.Given AABC is inscribed in the semicircle with diameter AB. The area of AABCarea of the semicircle. If the measure of the smallest angle in AABCthe measure of the smallest angle in AABC is x then sin 2x is equal toTAB. The area of AABC equals 2/9 of the

Answer»

BC²=AC²+AB² =8²+6² =64+36 =100

BC=10cm

Area of biggest semicircle= 1/2 * 3.14 * r² =0.5*3.14*5*5 =0.5*78.5 =39.25 cm²

Area of 2nd Largest Semicircle = 0.5*3.14*r² =0.5*3.14*3² =0.5*3.14*9 =14.13 cm²

Area of smallest Semicircle = 0.5*3.14*r² =0.5*3.14*4² =0.5*3.14*16 =25.12cm²

Area of Triangle = 1/2 *b*h = 0.5*6*8 =24 cm²

Area of shaded region = (24+25.12+14.13) - 39.25 = 63.25-39.25 =24 cm²