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Justify the following reaction is a redox reaction. CuO_((s)) + H_(2(g)) to Cu_((s)) + H_(2)O_((g)) |
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Answer» Solution :`OVERSET((+2)(-2))(CuO_((s))) + overset((o))(H_(2(g))) + overset((+1)(-2))(H_(2)O_(g))` n the above reaction, oxygen is removed from CuO. So CuO gets REDUCED. Oxygen is added to `H_(2)` to form WATER. So `H_(2)` gets oxidised, i.e. In CuO, OXIDATION number of CU +2 is reduced to 0 whereas in `H_(2)` , oxidation of `H_(2)` 0 is increased to +1. So the above reaction is a redox reaction |
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