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Jxf (x)sin 3x3 , ĺŻĺŻx=0. |
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Answer» f(x) = x/sin3x , when x ≠ 0 we know that when x→ 0, tye sinnx/x tends to n so sin3x/x → 3 => f(x) = x/sin3x = 1/3 , x≠0 and f(x) = 3 , when x = 0 SO, both are not equal , hence the function is discontinuous at x = 0 |
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