1.

क 2 800 707 sin 20° — 2cos 20° cosec 70°

Answer»

sec70= 1/cos70= 1/[sin(90-70)]= 1/sin20.cosec20 = 1/sin20= 1/[cos(90-20)]= 1/cos70.So, sec70sin20 - cos20cosec70= sin20/sin20 - cos20/cos20= 1 - 1= 0.

Please hit the like button if this helped you



Discussion

No Comment Found