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क 2 800 707 sin 20° — 2cos 20° cosec 70° |
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Answer» sec70= 1/cos70= 1/[sin(90-70)]= 1/sin20.cosec20 = 1/sin20= 1/[cos(90-20)]= 1/cos70.So, sec70sin20 - cos20cosec70= sin20/sin20 - cos20/cos20= 1 - 1= 0. Please hit the like button if this helped you |
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