1.

K_(2)Cr_(2)O_(7)+FeSO_(4)+H_(2)SO_(4)rarr K_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+Fe_(2)(SO_(4))_(3)+H_(2)O a) How many electrons are transferred b) What is the mole coefficient of H,30, in the above reaction?

Answer»

Solution :Change in oxidation STATE of Cr of `K_(2)Cr_(2)O_(7)`
=(2x +6) -(2x+3)=6
Change in oxidation state of Fe of `FeSO_(4)=+3-(+2)=1`
Cris -CROSSING the change `K_(2)Cr_(2)O_(7)-6FeSO_(4)`
(a) NUMBER of electrons transferred =6
(B) `K_(2)Cr_(2)O_(7)+6FeSO_(4)+7H_(2)SO_(4) to K_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+3Fe_(2)(SO_(4))_(3)+7H_(2)O`
Coefficient of `H_(2)SO_(4)=7`


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