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`K_(2)HgI_(4)` is 50% ionised in aqueous solution. Which of following are correct ?A. n = 7B. n = 3C. i = 2D. i = 4 |
Answer» Correct Answer - B::C Explanation : `K_(2)HgI_(4)rarr 2K^(+)+HgI_(4)^(2-)rArr n=3` `alpha=(i-1)/(n-1),0.5=(i-1)/(3-1)rArr i=2` `therefore` (b) and (c ) are correct while (a) and (d) are not correct. |
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