1.

`K_(2)HgI_(4)` is 50% ionised in aqueous solution. Which of following are correct ?A. n = 7B. n = 3C. i = 2D. i = 4

Answer» Correct Answer - B::C
Explanation : `K_(2)HgI_(4)rarr 2K^(+)+HgI_(4)^(2-)rArr n=3`
`alpha=(i-1)/(n-1),0.5=(i-1)/(3-1)rArr i=2`
`therefore` (b) and (c ) are correct while (a) and (d) are not correct.


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