1.

`k=4.95xx10^(-5) S cm^(-1)` for a `0.001 M `solution. The reciprocal of the degree of dissociation of acetic acid, if `wedge_(m)^(@)` for acetic acid is `400S cm^(-2) mol^(-1)` is `:`A. 7B. 8C. 9D. 10

Answer» Correct Answer - b
`k=4.95xx10^(-5)S cm^(-1), alpha=(wedge_(m))/(wedge^(@)._(m))`
`wedge_(m)=1000xx(k)/(C)=1000xx(4.95xx10^(-5))/(0.001)=49.5 S cm^(-1)`
`impliesalpha=(49.5)/(400)implies (1)/(alpha)=(400)/(49.5)~~8`


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