1.

K_(4)[Fe(CN)_(6)] is converted into CO_(3)^(-2), Fe^(+3) ions and NO_(3)^(-) ions. Here_____________

Answer»

N. is reduced
C. is oxidised
Iron is oxidised
Eq.wt `("Formula.wt")/(61)`

Solution :`{:(FE^(++)rarrFe^(+++),"(OX)",1xx1=1),(OVERSET(+2)(CN^(-))rarroverset(+4)(CO_(3)^(-2)),"(OX)",6xx2=12),(overset((-3))(CN^(-))rarroverset((+5))(NO_(3)^(-)),"(OX)",6xx8=48),(,,61):}`
n factor = 61


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