K_(a_1), K_(a_2) and K_(a_3), are the respective ionisation constants for the following reactions. H_2S hArr H^(+) + HS^(-) HS^(-) hArr H^(+) + S^(2-) H_2S hArr 2H^(+) + S^(2-) The correct relationship between K_(a_1),K_(a_2),K_(a_3) is

K_(a_1), K_(a_2) and K_(a_3), are the respective ionisation constants

1.	K_(a_1), K_(a_2) and K_(a_3), are the respective ionisation constants for the following reactions. H_2S hArr H^(+) + HS^(-) HS^(-) hArr H^(+) + S^(2-) H_2S hArr 2H^(+) + S^(2-) The correct relationship between K_(a_1),K_(a_2),K_(a_3) is
Answer» `K_(a_3) = K_(a_1) xx K_(a_2)` `K_(a_3) = K_(a_1) + K_(a_2)` `K_(a_3)=K_(a_1) - K_(a_2)` `K_(a_3)=K_(a_1) // K_(a_2)` Solution :For the reaction, `H_2S HARR H^(+)+ HS^(-)` `K_(a_1)=([H^+][HS^-])/([H_2S])` For this reaction, `HS^(-) hArr H^(+) + S^(2-)` `K_(a_2) = ([H^+][HS^(2-)])/([HS^-])` As, the above two reactions are added, their EQUILIBRIUM constants are MULTIPLIED, As `K_(a_3)=([H^+]^2[S^(2-)])/([H_2S]) K_(a_1)xxK_(a_2)` So `K_(a_3)= K_(a_3) xx K_(a_2)`