K_(a)for CH_(3)CO OH is 1.8xx10^(-5) and K_(b) for NH_(4)OHis 1.8xx10^(-5). The pH of ammonium acetate will be

K_(a)for CH_(3)CO OH is 1.8xx10^(-5) and K_(b) for NH_(4)OHis 1.8xx10^

1.	K_(a)for CH_(3)CO OH is 1.8xx10^(-5) and K_(b) for NH_(4)OHis 1.8xx10^(-5). The pH of ammonium acetate will be
Answer» 7.005 4.75 `7.0` between 6 and 7. Solution :`CH_(3)CO ONH_(4)` is a salt of weak acid and weak base. Hence, `PH = 7 + (1)/(2) (pK_(a) - pK_(b))=7+0=7`