K_a of NH_4^+ acid is 1.77xx10^(-5). Then give the equation and ionization constant of its conjugate base.

K_a of NH_4^+ acid is 1.77xx10^(-5). Then give the equation and ioniza

1.	K_a of NH_4^+ acid is 1.77xx10^(-5). Then give the equation and ionization constant of its conjugate base.
Answer» Solution :The CONJUGATE base of `NH_4^+`is `NH_3` and its IONIZATION CONSTANT is `K_b` So, `K_b=K_w/K_a=(1.0xx10^(-14))/(1.77xx10^(-5))=5.64xx10^(-10)`