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`K_(c) = 9` for the reaction, `A + B hArrC + D`. If A and B are taken in equal amounts, then amount of C in equilibrium is:A. 1B. `0.25`C. `0.75`D. None of these |
Answer» Correct Answer - C `{:(,A,+,B,hArr C,+,D),("Initial",1,1,,0,,0),("At equilibrium",(1-x),,(1-x),x,,x):}` `:.` `K_(c) = ([C][D])/([A][B]) =9` `:.` `(x.x)/((1-x)^(2)) =9` or `x^(2)=9+9x^(2)-18 x` or `8x^(2)-18x+9=0` `:.` `x=(3)/(2)` or `(3)/(4)` Hence, among the given options, option (c), i.e., `0.75` is correct. |
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