1.

K_(c)" for "CS_(2)(g)+4H_(2)(g)hArrCH_(4)(g)+2H_(2)S(g) is 0.28 at 900K. Calculate K_(p). (R = 8.314 JK^(-1)mol^(-1)).

Answer»

SOLUTION :`CS_(2)(g)+4H_(2)(g)hArrCH_(4)(g)+2H_(2)S(g)`
`Deltan=3-5=-2`
`K_(p)=K_(c)(RT)^(Deltan)" becomes "K_(p)=K_(c)(RT)^(-2)=(0.28)/((8.314xx900)^(2))=5XX10^(-9)`.


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