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`K_(f) of 1,4-"dioxane is" 4.9mol^(-1)` for `1000g`.The depression in freezing point for a`0.001m` solution in dioxane isA. `0.0049`B. `4.9+0.001`C. `4.9`D. `0.49` |
Answer» Correct Answer - A `Delta T=K_(f)xx` Molality `= 4.9xx0.001=0.0049 K` |
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