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K is the force constant of a spring. The work donein increasing its extension from `l_(1)` to `l_(2)` will beA. `(k)/(2) (l_(2)-l_(1))`B. `(k)/(2)(l_(2)^(2)-l_(1)^(2))`C. `k(l_(2)^(2)-l_(1)^(2))`D. `(k)/(2)(l_(2)^(3)-l_(1)^(3))` |
Answer» Correct Answer - B `u_(1)=(1)/(2)K l_(1)^(2) and u_(2) =(1)/(2)Kl_(2)^(2)` `u=(1)/(2) K(l_(2)^(2) -l_(1)^(2))` |
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