K_(p) for the reaction, NH_(4)HS(s) Leftrightarrow NH_(3) (g)+H_(2)S(g), at certain temperature is 4"bar"^(2). Calculate the equilibrium perssure.

K_(p) for the reaction, NH_(4)HS(s) Leftrightarrow NH_(3) (g)+H_(2)S(g

1.	K_(p) for the reaction, NH_(4)HS(s) Leftrightarrow NH_(3) (g)+H_(2)S(g), at certain temperature is 4"bar"^(2). Calculate the equilibrium perssure.
Answer» <P> Solution :Equilibrium constant, `K_(P)=P_(NH_(3)). P_(H_(2)S)=4"bar"^(2)` PARTIAL pressure are given as, `NH_(3)=P_(H_(2)S)=SQRT(K_(p))=2"bar"` `P_(NH_(3))+P_(H_(2)S)=2"bar" +2 "bar"=4 "bar"`