K_(sp) (BaSO_(4)) is1.1 xx 10^(10). In which case is BaSO_(4) precipit

1.	K_(sp) (BaSO_(4)) is1.1 xx 10^(10). In which case is BaSO_(4) precipitated ?
Answer» `100 mL of 4xx 10^(-3)M of BaCl _2 +300 mL of 6.0 XX 10^(-4)M of Na_2SO_4` ` 100 mLof 4xx 10^(-4)M of BaCl _2+ 300 mLof 6xx 10^(-8)M of Na_2SO_4` ` 300 mL of 4xx 10^(-4)M of BaCl_2 +100 mLof 6.0 xx 10 ^(-8)M of Na_2SO_4` in all cases Solution :Before MIXING ` [Ba^(+2) ]= 4 xx 10 ^(_3)M rArr [SO_4^(-2)] = 6 xx 10 ^(-4)M ` after mixing, ` 4 xx 10 ^(-3)xx 100 =M_2xx 400` ` [ Ba^(+2) ] = 10 ^(-3) M` ` 6 xx 10 ^(-4) xx 300 = M_2 xx 400` ` [SO_4^(-2) ]=4.5 xx 10^(-4)M` ` IP=[Ba^(+2) ][SO_4^(-2) ]= 4.5 xx 10 ^(-7),KsPlt I.P.`

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