K_(sp) of BaSO_4=1.05xx 10^(-10) at same temperature is the concentration of Ba^(2+) and SO_4^(2-) in saturated solution.

K_(sp) of BaSO_4=1.05xx 10^(-10) at same temperature is the concentrat

1.	K_(sp) of BaSO_4=1.05xx 10^(-10) at same temperature is the concentration of Ba^(2+) and SO_4^(2-) in saturated solution.
Answer» Solution :The ionic equilibrium in concentratedof `BaSO_4` is under. `BaSO_(4(s)) hArr Ba_((AQ))^(2+) + SO_(4(aq))^(2-)` So, `K_(sp)=[BA^(2+)][SO_4^(2-)]` but `[Ba^(2+)]=[SO_4^(2-)]`= solubility S MOL `L^(-1)` `K_(sp)=(S) (S) =S^2 =1.05xx10^(-10)` `therefore S=[Ba^(2+)]=[SO_4^(2-)]` `=(1.05xx10^(-10))^(1/2)` `=1.0247xx10^(-5) "mol L"^(-1)`