`K_(SP)` of `BaSO_(4)` is `1.5xx10^(-9)` . Calculate is solubility in: (a) Pure water, , (b) `0.10MBaCI_(2)`.

`K_(SP)` of `BaSO_(4)` is `1.5xx10^(-9)` . Calculate is solubility in:

1.	`K_(SP)` of `BaSO_(4)` is `1.5xx10^(-9)` . Calculate is solubility in: (a) Pure water, , (b) `0.10MBaCI_(2)`.
Answer» `BaSO_(4)hArr underset(S)(Ba^(2+))+underset(S)(SO_(4)^(2-))` (where S in m/litre solubility of `BaSO_(4)`) (i) `K_(SP)=SxxS` `:. S=sqrt(K_(SP))=sqrt(1.5xx10^(-9))` `= 3.87xx10^(-5)` mol `litre^(-1)` (ii) In presence of `0.10M BaCI_(2)`, let S mol/litre `BaSO_(4)` is dissolved `K_(SP)=[Ba^(2+)][SO_(4)^(2-)]` `1.5xx10^(-9)=(0.1+S)(S)` `[(0.1+S)=0.1 as S ltltlt0.1]` `:. S=1.5xx10^(-8)M`

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`K_(SP)` of `BaSO_(4)` is `1.5xx10^(-9)` . Calculate is solubility in: (a) Pure water, , (b) `0.10MBaCI_(2)`.

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