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K_(sp) of M(OH)_(x), is 27 xx 10^(-12) and its solubility in water is 10^(-3) mol litre^(-1) . Find the value of X |
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Answer» ` K_(sp)=S(XS)^(x) ` ` 27 XX 10 ^(-12)= (10 ^(-3)) ( X 10 ^(-3)) ^(x) ` ` 27 xx 10 ^(_12)= 10 ^(-3-3x), X^(x) rArr 3^(3) =27 ,x=3` |
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