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| 1. |
K_(sp) of PbI_2 is 1xx10^(-8) .Then what is the solubility of PbI_2 in 0.1 M KI ? |
| Answer» SOLUTION :`y=K_(sp)/[I^-]^2=(1xx10^(-8))/(0.1)^2=1xx10^(-6)` M (Solubility in pressure of COMMON ION) | |