1.

K_w=1xx10^(-14) calculate the concentration of [H_3O^+] in 10^(-8)M HCl.

Answer»

`1.0xx10^(-8)` M
`1.0525xx10^(-7)` M
`1.0xx10^(-6)` M
`9.525xx10^(-8)`M

Solution :`[HCl]=[H_3^+ O]= 1xx10^(-8)` M
`10^(-8) M LT 1 xx 10^(-7)M` of `H_3O^+`
`THEREFORE` Total `[H_3O^+]=(1xx10^(-8)+1xx10^(-7))`
`=1.1xx10^(-7) approx 1.0525xx10^(-7)` M
`[H^+][OH^-]=10^(-14)`
`therefore (10^(-8)+X)x=10^(-14)=0`
`therefore x=9.5xx10^(-8)`
Total `[H^+]=1xx10^(-8)+9.5xx10^(-8)`
`=1.05xx10^7` M


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