KCl crystallises in the same type of lattice as does NaCl. Given that r_(Na^+)//r_(Cl^-)=0.55 and r_(K^+)// r_(Cl^-)=0.74 . Calculate the ratio of the side of the unit cell of KCl to that of NaCl

KCl crystallises in the same type of lattice as does NaCl. Given that

1.	KCl crystallises in the same type of lattice as does NaCl. Given that r_(Na^+)//r_(Cl^-)=0.55 and r_(K^+)// r_(Cl^-)=0.74 . Calculate the ratio of the side of the unit cell of KCl to that of NaCl
Answer» 1.123 0.891 1.414 0.414 Solution :We AIM at :`(r_(K^+)+r_(Cl^-))//(r_(Na^+)+r_(Cl^-))` Given `r_(Na^+)/r_(Cl^-)=0.55`and `r_(K^+)/r_(Cl^-)`=0.74 `r_(Na^+)/r_(Cl^-)+1=1.55` and `r_(K^+)/r_(Cl^-)+1=1.74` i.e., `(r_(Na^+)+r_(Cl^-))/(r_(Cl^(-)))=1.55` `(r_(K^+)+r_(Cl^-))/(r_(Cl^(-)))=1.74` Dividing (II) by (i) , `(r_(K^+)+r_(Cl^-))/(r_(NA^+)+r_(Cl^-))=1.74/1.55`=1.123