KCl crystallizes in the same type of lattice as does NaCl. Given that r_(Na+)//r_(Cl-)=0.55 and r_(K+)//r_(Cl-)=0.74. Calculate the ratio of the side of the unit cell of KCl to that of NaCl.

KCl crystallizes in the same type of lattice as does NaCl. Given that

1.	KCl crystallizes in the same type of lattice as does NaCl. Given that r_(Na+)//r_(Cl-)=0.55 and r_(K+)//r_(Cl-)=0.74. Calculate the ratio of the side of the unit cell of KCl to that of NaCl.
Answer» 1.123 0.891 1.414 0.414 Solution :Our aimis `(r_(K^+)+r_(Cl^-))//(r_(Na^+)+r_(Cl^-))` `"Given"(r_(Na^+))/(r_(Cl^-))=0.55` `and(r_(K^+))/(r_(Cl^-))=0.74` `therefore(r_(Na^+))/(r_(Cl^-))+1=1.55` and`(r_(K^+))/(r_(Cl^-))+1=1.74` `i.e.,(r_(Na^+)+r_(Cl^-))/(r_(Cl^-))=1.55""....(i)` and`(r_(K^+)+r_(Cl^-))/(r_(Cl^-))=1.74"".......(II)` `"Dividing"(ii)"by"(i)`, `(r_(K^+)+r_(Cl^+))/(r_(Na^+)+r_(Cl^-))=(1.74)/(1.55)=1.125`