KCl crystallizes int the same type of lattic as done NaCl . Given that `r_(Na^(+))//r_(Cl^(-)) = 0.50` and `r_(Na^(+))//r_(K^(+)) = 0.70` , Calcualte the ratio of the side of the unit cell for KCl to that for NaCl:

KCl crystallizes int the same type of lattic as done NaCl . Given that

1.	KCl crystallizes int the same type of lattic as done NaCl . Given that `r_(Na^(+))//r_(Cl^(-)) = 0.50` and `r_(Na^(+))//r_(K^(+)) = 0.70` , Calcualte the ratio of the side of the unit cell for KCl to that for NaCl:
Answer» `(r_(Na^(+)))/(r_(Cl^(-)))=0.55, (r_(Na^(+)))/(r_(Cl^(-)))+1=1.55` `(r_(K^(+)))/(r_(Cl^(-)))=0.74, (r_(K^(+)))/(r_(Cl^(-)))+1=1.74` Dividing (ii) by (i), `(r_(K^(+))+r_(Cl^(-)))/(r_(Na^(+))+r_(Cl^(-)))=(1.74)/(1.55)=1.122`

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KCl crystallizes int the same type of lattic as done NaCl . Given that `r_(Na^(+))//r_(Cl^(-)) = 0.50` and `r_(Na^(+))//r_(K^(+)) = 0.70` , Calcualte the ratio of the side of the unit cell for KCl to that for NaCl:

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