Kclo3 on heating gives kcl and O2 .What is the volume of O2 liberated

1.	Kclo3 on heating gives kcl and O2 .What is the volume of O2 liberated by 0.1 mole of Kclo3.
Answer» 3.36 Litres The decomposition of KClO3 on heating is called as thermal decomposition reaction. The Chemical Equation showing this reaction: 2KClO3 ----heating---> 2KCl + 3O2 2 MOL 3 mol Calculating how much 2 MOLES of KClO3 evolve Oxygen at N.T.P = 3 x 22.4 L = 67.2 Litres Calculating how much 1 mole of KClO3 evolve Oxygen at N.T.P: For this we take 2 to the other side of the equation = 67.2 / 2 Litres = 33.6 Litres Now, Calculating how much 0.1 mole of KClO3 evolve Oxygen at N.T.P = 67.2 / 2 x 0.1 L = 3.36 Litres Therefore, the VOLUME of O2 LIBERATED by 0.1 mole of KClO3 is 3.36 Litres.

Kclo3 on heating gives kcl and O2 .What is the volume of O2 liberated by 0.1 mole of Kclo3.

Answer»

The decomposition of KClO3 on heating is called as thermal decomposition reaction.

The Chemical Equation showing this reaction:

2KClO3 ----heating---> 2KCl + 3O2

2 MOL 3 mol

Calculating how much 2 MOLES of KClO3 evolve Oxygen at N.T.P

= 3 x 22.4 L

= 67.2 Litres

Calculating how much 1 mole of KClO3 evolve Oxygen at N.T.P:

For this we take 2 to the other side of the equation

= 67.2 / 2 Litres

= 33.6 Litres

Now,

Calculating how much 0.1 mole of KClO3 evolve Oxygen at N.T.P

= 67.2 / 2 x 0.1 L

= 3.36 Litres

Therefore, the VOLUME of O2 LIBERATED by 0.1 mole of KClO3 is 3.36 Litres.