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Keeping the density of the earth constant, if the radius of the earth decreases by 2% , what would be thechange in ‘g.? |
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Answer» Solution : Relation between acceleration DUE to gravity g and radius of earth (R) in terms of density is `g = 4/3 pi Grho. R` When density is kept CONSTANT and radius is DECREASED by 2% then `(Delta R)/(R) XX 100 = 2` from distribution of errors in multiplications and divisions `(Delta g)/(g) xx 100 = (Delta R)/(R) xx 100 = 2%` When density is constant and radius of earth decreases by 2% then decrease in g value is also 2%. |
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