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Keeping the mass of the earth constant, if the radius of the earth decreases by 2%. What would be the change in .g.? |
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Answer» Solution : We know that the relation between .g. and .G. is g= `(GM)/(R^2)` When mass is kept as constant and radius is decreased by 2% then`(Delta R)/( R) xx 100 = 2` From DISTRIBUTION of errors in MULTIPLICATIONS and DIVISIONS`(Delta g)/(g) xx 100 = -2(DeltaR)/(R) xx 100` % change in `g=-2 xx 2 = -4% ` -ve sign indicates that when R decreases .g. increases. |
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