1.

Keeping the velocity of projection constant, the angle of projection is increased from 0^(0) to 90^(@). Then the maximum height of the projectile

Answer»

goes on INCREASING up to `90^(@)`
decreases up to `90^(@)`
INCREASE up to `45^(@)` and decreases BEYOND it
decreases up to `45^(@)` and beyond it

Answer :A


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