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Keeping the volume constant, the pressure of a gas is increased by 10% of its original value by increasing the temperature from 27^(@)C. Find the final temperature. |
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Answer» <P> SOLUTION :INITIAL pressure of the gas `(P_(1))=P`Final pressure of the gas `(P_(2))=110/100P` , Initial temperature `t_(1)^(@)C=27^(@)C` `T_(1)=27+273=300K` , Final temperature `t_(2)^(@)C=?` At constant VOLUME, according to Charles law `P_(1)/T_(1)=P_(2)/T_(2)` `T_(2)=P_(2)/P_(1)T_(1)=(110P//100)/P times 300=330 rArr t_(2)=330-273=577^(@)C`. |
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