KIO_(3)+5KI+6HCl to 3I_(2)+6KCl+3H_(2)O Correct statement of this reac

1.	KIO_(3)+5KI+6HCl to 3I_(2)+6KCl+3H_(2)O Correct statement of this reaction is
Answer» `I^(-)` is REDUCED to `I_(2)` `IO_(3)^(-)` is oxidised to `I_(2)` `IO_(3)^(-)` is reduced to `I_(2)` OXIDATION number of I decreases from 01 (in KI) to zero `("in "I_(2))` Answer :C

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