KJ in 5mol HCl, how to calculate it?

1.	KJ in 5mol HCl, how to calculate it?
Answer» ANSWER: Amount of HEAT RELEASED when one mole of strong acid reacts with one mole of the strong BASE =−57.1 KJ 0.5HCl+0.5NaOH⟶0.5NaCl+0.5H 2 O Amount of heat released = 2 −57.1 =−28.55 kJ

Answer»

Amount of HEAT RELEASED when one mole of strong acid reacts with one mole of the strong BASE =−57.1 KJ

0.5HCl+0.5NaOH⟶0.5NaCl+0.5H

Amount of heat released =

−57.1

=−28.55 kJ

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