`KMnO_(4)` can be prepared from `K_(2)MnO_(4)` as per reaction `3MnO_( – InterviewSolution

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1.	`KMnO_(4)` can be prepared from `K_(2)MnO_(4)` as per reaction `3MnO_(4)^(2-)+2H_(2)OhArr2MnO_(4)^(-)+MnO_(2)+4OH^(-)`A. HClB. KOHC. `CO_(2)` is formed as the productD. `sO_(2)`
Answer» Correct Answer - D Since,`OH^(-)` are generated from weak acid`(H_(2)O)`. A weak acid (like `CO_(2)`) should be used to remove it because strong acid (HCl) reverse the reaction . KOH increases the concentration of `OH^(-)`,thus again sgifts the reaction in backward side . `Co_(2)` combines with `OH^(-)` to give carbonate which is easily removed. `SO_(2)`react with water to give strong acid , so it cannot be used.

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