1.

Knowing that `K_(sp)` for `AgCl` is `1.0 xx 10^(-10)`, calculate `E` for a silver `//` silver chloride electrode immersed in `1.00 M KCl ` at `25^(@)C.E^(c-)._(Ag^(o+)|Ag)=0.799V`.

Answer» `K_(sp)(AgCl)=[Ag^(o+)][Cl^(c-)],KCl=1.00M`
`:. [Cl^(c-)]=1.00M`
`:. [Ag^(o+)]=(K_(sp))/([Cl^(c-)])=(1.0xx10^(-10))/(1.00)=1.0=10^(-10)`
`Ag^(o+)+e^(-)rarr Ag" "E^(c-)._(Ag^(o+)|Ag)=0.799V`
`:. E=E^(c-)-(0.059)/(1)log.(1)/([Ag^(o+)])`
`=0.799-(0.059)/(1)log.(1)/((0.10xx10^(-10))`
`=0.799=0.592=0.207V`


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