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क्षेत्रीदरम्यान ऊच-याचे ग्यास्यामनगरी करणार​

Answer»

Let distance between Manipur DISPUR = x kmAverage speed of train from Manipur \( \Large = \FRAC{x}{4} km/h \)Average speed of train from Dispur \( \Large = \frac{2x}{7} km/h \)Let they meet y h after 6 : 00 am.Then, according to the question,\( \Large \left(\frac{x}{4} \times y\right)+\frac{2x}{7} \times \left(y-2\right) = x \)\( \Large \frac{y}{4}+\frac{2 \left(y-2\right) }{7} = 1 \)7y+8(y-2) = 2815y = 44Y = \( \Large 15Y = 44 \) = 2 h 56 minClearly, trains meet 2 h 56 min after 6 : 00 am.It means the trains meet at 8 : 56 am



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