Latent heat of fusion of ice is 6 kJ mol^(-1). Calculate the entropy change in the fusion of ice.

Latent heat of fusion of ice is 6 kJ mol^(-1). Calculate the entropy c

1.	Latent heat of fusion of ice is 6 kJ mol^(-1). Calculate the entropy change in the fusion of ice.
Answer» Solution :CHANGE in entropy, `DeltaS = q_(rev)//T` `q_(rev)`= Latent heat of fusion = `6 kJ mol^(-1)` `= 6000 J mol^(-1)` T = Freezing point of water = 273K. `DeltaS = 6000/(273 = 21.98 JK^(-1) mol^(-1)) (or)` `DeltaS = (6000)/(273 XX 18) = 1.22 JK^(-1)g^(-1)`.